Two points are 10 units apart on the coordinate plane. Ifan ant were to walk between the 2 points moving onlyvertically and horizontally, it would have to walk 6 horizontalunits. How many vertical units would the ant have to walk?

Answer:The vertical distance the ant have to walk is 8 unitsStep-by-step explanation:∵ The ant must be walk vertically and horizontally∴ The distance from start point to end point will be as    a hypotenuse of a right angle triangle∵ The ant would have to walk 6 units horizontally that    means one side of the right angle is 6 units∵ The two points are apart by 10 units that means    the length of the hypotenuse is 10 units∴ The vertical distance the ant would have to walk is    the length of the second side of the right angle* By using Pythagoras Theorem:∵ (hypotenuse)² = (horizontal leg)² + (vertical leg)²∴ 10² = 6² + (vertical leg)²∵ (vertical leg)² = 100 - 36 = 64∴ Vertical leg  = √64 = 8 units∴ The vertical distance the ant have to walk is 8 units