What is the slope of the line with equation y-3=-1/2(x-2)

Given parameters: Equation of the straight line;               y - 3  = [tex]\frac{-1}{2}[/tex](x -2)We can determine the slope of any straight line from the equation of such lines. Generally, a straight line has the formula;                    y  = mx  + C where y is the y-axis coordinate and x is the x-axis coordinate            m is the slope and c is the y-axis interceptNow let us express the given equation in this format;              y - 3  = [tex]\frac{-1}{2}[/tex](x - 2)Multiply both sides by 2;       2(y - 3) = -1(x -2)         2y -6 = -x + 2Rearrange to the form y = mx + c        2y  = -x + 2 + 6        2y  = -x + 8    divide by 2;          y = [tex]\frac{-1}{2}[/tex]x + 4         y = mx + cthe slope is m and it is equal to [tex]\frac{-1}{2}[/tex]